1. Pick the number of times a week that you would like to go out to eat. (more than once but less than 10)

2. Multiply this number by 2 (just to be bold)

3. Add 5

4. Multiply it by 50

5. If you have already had your birthday this year add 1756. If you haven't, add 1755.

6. Now subtract the four digit year that you were born.

You should have a three digit number

The first digit of this was your original number (I.e., how! Many times you want to go out to restaurants in a week.)

The next two numbers are

YOUR AGE! (Oh YES, it is!!!!!)

THIS IS THE ONLY YEAR (2006) IT WILL EVER WORK, SO SPREAD IT AROUND WHILE IT LASTS

SOLUTION
I'll assume you have had your birthday this year(2006) and use 1756 in the calculation. Actually, you can continue to use 1756 until you have your birthday in 2007.

We will also let n be the number of times you want to go out to eat, and let b represent the year of your birth.

Here is the algebra. If you go through the formula Jerry gave us you get:
(2n+5)50 + 1756 - b.

Then I break it down algebraically (remember how to do this?)
(2n+5)50 + 1756 - b = 100n + 250 + 1756 - b
           = 100n + (250 + 1756 - b) = 100n + (2006 - b)

Look at the term 2006 - b. That number is the age you turned in 2006 if you have already had your birthday this year. Jerry is assuming that anyone who works the puzzle has a one or two digit age. If someone who is 103 does the puzzle, it does not work.

The other part, 100n, is the 100's place in the number you calculate. For example if you like to go out to eat 4 times per week, 100n will be 400.

So, if you were born April 12, 1945 and like to go out to eat 4 times per week, your resulting number will be 400 + (2006 - 1945) = 461 since you turned 61 in 2006.

To make the puzzle work in 2007, use 1757 if you have already had your birthday and 1756 if you have not.